WebB) 50 degrees C) 100 degrees D) 130 degrees E) 140 degrees E C A B D 2 1.5 6 4.5 4 3 B A U S P Q T R E A C B D. 6. If the area of ABC is 3 square units, and the lengths ... and segment AC is tangent to the circle at B. Segment AD intersects the circle at F and ... In ABC AB = 10, BC = 8, CA = 9. If B is the midpoint of AX, ZC is 3 times CA, and ... WebIn ΔABC, if AB=AC and ∠B=50 0, then ∠A is equal to: A 40 0 B 50 0 C 80 0 D 130 0 Medium Solution Verified by Toppr Correct option is C) Given, AB=AC and ∠B=50 o We have to find ∠A As ∠B=50 o, we have ∠C=50 o Therefore, ∠A+∠B+∠C=180 o ⇒50+50+∠A=180 o ⇒100+∠A=180 o ⇒∠A=80 o Was this answer helpful? 0 0 Similar questions
Consider a right triangle ABC, right angled at B and If AC = 17 units …
WebIn ∆ABC, ∠Α = 50°, ∠B = 70° and bisector of ∠C meets AB in D (Fig. 6.17). Measure of ∠ADC is (a) 50° (b) 100° (c) 30° (d) 70° Solution: Given, ABC is a triangle. ∠Α = 50° and ∠B = 70° The bisector of ∠C meets AB in D. We have to find the measure of ∠ADC. Considering triangle ADC, By angle sum property of a triangle, WebSolution: Given: In a Δ ABC, AB = AC and ∠B = 70° ∠ B = ∠ C [Angles opposite to equal sides of a triangle are equal] Therefore, ∠ B = ∠ C = 70° Sum of angles in a triangle = 180° ∠ A + ∠ B + ∠ C = 180° ∠ A + 70° + 70° = 180° ∠ A = 180° – 140° ∠ A = 40° Practice Problems Q.1: PQR is a triangle in which PQ = PR and is any point on the side PQ. incompatibility\u0027s ir
In ABC, if AB = AC and ∠ B =50∘, then ∠ C is equal toA. 40∘B. 50∘C. 80∘
WebMar 17, 2024 · The angle sum property of a triangle states that the sum of the measures of the three interior angles of a triangle is always 180 ∘ . Therefore, in triangle ABC, we get ∠ A + ∠ B + ∠ C = 180 ∘ Substituting ∠ B = 50 ∘ and ∠ C = 50 ∘ in the equation, we get ⇒ ∠ A + 50 ∘ + 50 ∘ = 180 ∘ This is a linear equation in terms of ∠ A . Web$\begingroup$ You can express $\angle C$ and $\angle B$ in terms of $\angle A$. Using the Law of sines and the formula of sine of sum of angles you get to: $$\frac{10}{\cos (A/2)} = \frac{4}{\sin (3A/2)} = \frac{BC}{\sin A}$$ $\endgroup$ WebTranscribed Image Text: Triangles ABC and ACD are similar. A = 5 cm Angle BAC angle CAD. Angle ABC = angle ACD. AB= 5 cm and AC = 8 cm. (a) Calculate the length of AD. B cm D Diagram NOT accurately drawn cm incompatibility\u0027s iv